Question

1. julieta drives a truck. her speed for the first half of a trip to another city is shown by the speedometer on the left. her speed for the second half of the same trip is shown by the speedometer on the right. what was julietas average speed for this trip?

Explanation:

Step1: Determine speeds for each half - trip

The speed for the first half of the trip from the left speedometer is 65 mph. The speed for the second half of the trip from the right speedometer is 50 mph.

Step2: Use the formula for average speed (when distances are equal)

The formula for average speed $v_{avg}$ when the distances of two parts of a trip are equal is $v_{avg}=\frac{2v_1v_2}{v_1 + v_2}$, where $v_1$ and $v_2$ are the speeds of the two parts. Here, $v_1 = 65$ mph and $v_2=50$ mph.
Substitute the values into the formula: $v_{avg}=\frac{2\times65\times50}{65 + 50}=\frac{6500}{115}=\frac{1300}{23}\approx56.52$ mph.

Answer:

$\frac{1300}{23}\approx56.52$ mph