Question

jose is practicing punnett squares. based on this sample, which box did he not fill out correctly?
a.
b.
c.
d.

Explanation:

Step1: Analyze Punnett Square Rules

A Punnett square for \(Dd\times Dd\) (assuming parents' genotypes). The gametes from each parent are \(D\) and \(d\). When filling the square, we combine gametes. The possible combinations are \(DD\) (from \(D\times D\)), \(Dd\) (from \(D\times d\)), \(dD\) (equivalent to \(Dd\) as per Mendelian genetics, gene order doesn't matter for heterozygotes in simple dominance cases), and \(dd\) (from \(d\times d\)).

Step2: Check Each Box

• Box \(a\): If it's \(DD\), it's correct as \(D\times D = DD\).
• Box \(b\): If it's \(Dd\), it's correct as \(D\times d=Dd\) (or \(d\times D = Dd\)).
• Box \(c\): If it's \(DD\), it's correct as \(D\times D = DD\) (assuming one parent contributes \(D\) and the other \(D\)).
• Box \(d\): If it's \(dd\), it's wrong. Because for \(Dd\times Dd\), the bottom - left box (assuming standard Punnett square setup where rows are one parent's gametes and columns are the other's) should be \(dD\) (i.e., \(Dd\)), not \(dd\). The \(dd\) combination comes from \(d\times d\), but in a standard \(Dd\times Dd\) Punnett square (with rows as \(D\) and \(d\) for one parent and columns as \(D\) and \(d\) for the other), the bottom - left cell is \(d\times D=Dd\).

Answer:

d.