Question

jogger 1 in the figure has a mass of \\(61.3\text{ kg}\\) and runs in a straight line with a speed of \\(3.35\text{ m/s}\\).

part a
what is the magnitude of the joggers linear momentum?
\\(p = \\) \\(\text{kg}\cdot\text{m/s}\\)

Explanation:

Identify the given values

We are given the following values for Jogger 1:

• Mass \(m = 61.3\text{ kg}\)
• Speed \(v = 3.35\text{ m/s}\)

State the formula for linear momentum

The magnitude of linear momentum \(p\) is defined as the product of an object's mass and its speed:

$$p = m \cdot v$$

Calculate the magnitude of momentum

Substitute the given values into the formula:

$$p = 61.3\text{ kg} \times 3.35\text{ m/s}$$

$$p = 205.355\text{ kg}\cdot\text{m/s}$$

Round to appropriate significant figures

The given values \(61.3\text{ kg}\) and \(3.35\text{ m/s}\) both have three significant figures. Rounding the result to three significant figures gives:

$$p \approx 205\text{ kg}\cdot\text{m/s}$$

Answer:

What is the magnitude of the jogger's linear momentum?

\(p =\) <blank>\(205\)</blank> \(\text{kg}\cdot\text{m/s}\)