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integrated math i 5.2 solving systems by substitu solve each system by …

Question

integrated math i
5.2 solving systems by substitu
solve each system by substitution.

  1. y=-x-1 y=-2x+3

Explanation:

Step1: Substitute y from first equation

Since \( y = -x - 1 \) and \( y = -2x + 3 \), substitute \( y \) in the second equation with \( -x - 1 \):
\( -x - 1 = -2x + 3 \)

Step2: Solve for x

Add \( 2x \) to both sides:
\( -x + 2x - 1 = 3 \)
\( x - 1 = 3 \)
Add 1 to both sides:
\( x = 3 + 1 \)
\( x = 4 \)

Step3: Find y using x=4

Substitute \( x = 4 \) into \( y = -x - 1 \):
\( y = -4 - 1 \)
\( y = -5 \)

Answer:

The solution to the system is \( x = 4 \), \( y = -5 \) (or the ordered pair \( (4, -5) \))