Question

imagine a beaker divided down the center by a rigid membrane that is freely permeable to water but impermeable to glucose. side 1 contains a 10 percent glucose solution and side 2 contains the same volume of pure water. at equilibrium, what will be the situation?

the volume of liquid will be greater in side 2.

water will continue to move from side 2 to side 1.

the volume of liquid will be greater in side 1.

water will continue to move from side 1 to side 2.

the volume of liquid remains equal on both sides.

Explanation:

This problem involves osmosis, a concept in Biology (Natural Science subfield). Osmosis is the movement of water across a semi - permeable membrane from an area of lower solute concentration to an area of higher solute concentration. Side 1 has a 10% glucose solution (higher solute concentration), and Side 2 has pure water (lower solute concentration). So water will move from Side 2 to Side 1 until equilibrium. At equilibrium, since water moved into Side 1, the volume of liquid will be greater in Side 1. Also, at equilibrium, the net movement of water stops, so the options about continuous movement are incorrect. The option about equal volume is wrong as osmosis causes a volume change, and the option about greater volume in Side 2 is wrong as water moves into Side 1.

Answer:

C. The volume of liquid will be greater in side 1.