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Identify the algebraic identities
We use the given formulas for the sum and difference of cubes:
- Sum of cubes: \((a + b)(a^2 - ab + b^2) = a^3 + b^3\)
- Difference of cubes: \((a - b)(a^2 + ab + b^2) = a^3 - b^3\)
Analyze options with linear factor \((x - 4)\) or \((x + 4)\)
Using Polynomial Operations, we test \(a = x\) and \(b = 4\):
- For \((x - 4)\), we need \(a^2 + ab + b^2 = x^2 + 4x + 16\).
- Option 1: \((x - 4)(x^2 + 4x - 16)\) does not match.
- For \((x + 4)\), we need \(a^2 - ab + b^2 = x^2 - 4x + 16\).
- Option 5: \((x + 4)(x^2 - 4x + 16)\) matches perfectly.
- Option 6: \((x + 4)(x^2 + 4x + 16)\) does not match.
Analyze options with linear factor \((x - 1)\) or \((x + 1)\)
Using Polynomial Multiplication, we test \(a = x\) and \(b = 1\):
- For \((x - 1)\), we need \(a^2 + ab + b^2 = x^2 + x + 1\).
- Option 2: \((x - 1)(x^2 - x + 1)\) does not match.
- Option 3: \((x - 1)(x^2 + x + 1)\) matches perfectly.
- For \((x + 1)\), we need \(a^2 - ab + b^2 = x^2 - x + 1\).
- Option 4: \((x + 1)(x^2 + x - 1)\) does not match.
Select the correct options
The products that result in a sum or difference of cubes are:
- \((x - 1)(x^2 + x + 1) = x^3 - 1\)
- \((x + 4)(x^2 - 4x + 16) = x^3 + 64\)
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- (A) \((x - 4)(x^2 + 4x - 16)\)
- (B) \((x - 1)(x^2 - x + 1)\)
- (C) \((x - 1)(x^2 + x + 1)\) (Correct answer)
- (D) \((x + 1)(x^2 + x - 1)\)
- (E) \((x + 4)(x^2 - 4x + 16)\) (Correct answer)
- (F) \((x + 4)(x^2 + 4x + 16)\)