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Identify the missing binomials from the options
The options represent the expanded form of the product of two binomials:
- \(-15c^4 - 7c^2d + 2d^2\)
- \(-15c^4 + 7c^2d + 2d^2\)
- \(-15c^4 + 13c^2d + 2d^2\)
- \(-15c^4 + 13c^2d - 2d^2\)
To produce a leading term of \(-15c^4\) and a constant/last term of \(\pm 2d^2\), the binomials must be of the form \((3c^2 + ad)( -5c^2 + bd)\) or similar.
Let's test factors of \(-15\) and \(\pm 2\):
If the binomials are \((3c^2 + 2d)(-5c^2 + d)\):
This matches the first option.
If the binomials are \((3c^2 - 2d)(-5c^2 - d)\):
This matches the second option.
If the binomials are \((5c^2 + 2d)(-3c^2 + d)\):
If the binomials are \((5c^2 - d)(-3c^2 - 2d)\):
If the binomials are \((3c^2 - d)(-5c^2 - 2d)\):
If the binomials are \((3c^2 + d)(-5c^2 + 2d)\):
If the binomials are \((5c^2 + d)(-3c^2 + 2d)\):
If the binomials are \((5c^2 - 2d)(-3c^2 - d)\):
Let's check the options with \(13c^2d\):
If the binomials are \((15c^2 + 2d)(-c^2 + d)\):
This matches the third option perfectly when multiplying the standard binomials \((15c^2 + 2d)\) and \((-c^2 + d)\).
Expand the standard binomials
Let the given binomials be \((15c^2 + 2d)\) and \((-c^2 + d)\):
Simplify the terms
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- (A) \(-15c^4 - 7c^2d + 2d^2\)
- (B) \(-15c^4 + 7c^2d + 2d^2\)
- (C) \(-15c^4 + 13c^2d + 2d^2\) (Correct answer)
- (D) \(-15c^4 + 13c^2d - 2d^2\)