Question

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Explanation:

1. A series circuit requires all components (3 bulbs, 2 cells, switch, ammeter) connected in a single loop. The voltmeter must be parallel to the second bulb to measure its voltage.
2. For only one bulb to turn off when the switch opens, the circuit must be a combination: two bulbs in parallel, and the third bulb in series with the switch. Opening the switch breaks the path for the third bulb but leaves the parallel pair on.

Answer:

1. Draw a series circuit: Two cells (battery) → switch → ammeter → bulb 1 → bulb 2 → bulb 3 → back to battery. Connect voltmeter parallel across bulb 2.
2. Draw a mixed circuit: Two cells → main path splits into two branches: Branch 1 (bulb 1) and Branch 2 (switch + bulb 2). Both branches rejoin to connect to bulb 3 → back to battery. (Or any configuration where one bulb is in series with the switch, others in parallel/separate paths.)