Question

if, however, you score below 60%, you will need to proceed through the items in this module to prepare for the module exam. question 12 1 pts which is the value of $\sec^{2}80^{\circ}-\tan^{2}80^{\circ}$? 1 undefined 0 -1

Explanation:

Step1: Recall Pythagorean identity

$\sec^2 \theta - \tan^2 \theta = 1$ for any valid $\theta$

Step2: Substitute $\theta = 80^\circ$

$\sec^2 80^\circ - \tan^2 80^\circ = 1$

Answer:

1