Question

1. how would an objects acceleration be calculated base upon the following given information

vi = 12 meters per second
vf = 36 meters per second
ti = 4 meters per second
tf = 10 meters per second

(36 + 12)/(10 + 4)

(36 - 12)/(10 - 4)

(36 12)/(10 4)

(36/12)/(10/4)

clear all

Explanation:

Step1: Recall the acceleration formula

Acceleration \(a=\frac{v_{f}-v_{i}}{t_{f}-t_{i}}\), where \(v_{f}\) is the final velocity, \(v_{i}\) is the initial velocity, \(t_{f}\) is the final time, and \(t_{i}\) is the initial time.

Step2: Substitute the given values

Given \(v_{i} = 12\space m/s\), \(v_{f}=36\space m/s\), \(t_{i} = 4\space s\), \(t_{f}=10\space s\). Substituting into the formula gives \(a=\frac{36 - 12}{10 - 4}\).

Answer:

\(\frac{36 - 12}{10 - 4}\) (corresponds to the second option in the multiple - choice list)