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how can $\\triangle wxy$ be mapped to $\\triangle mnq$? translate verte…

Question

how can $\triangle wxy$ be mapped to $\triangle mnq$? translate vertex $w$ to vertex $m$, then reflect across the line containing \underline{\hspace{3cm}}. \bigcirc \overline{wx} \bigcirc \overline{wy} \bigcirc \overline{xy} \bigcirc \overline{mq}$

Explanation:

Step1: Analyze side lengths

In $\Delta WXY$: $WY=30\,\text{cm}$, $WX=18\,\text{cm}$. In $\Delta MNQ$: $MQ=30\,\text{cm}$, $MN=18\,\text{cm}$.

Step2: Check mapping condition

Translating $W$ to $M$ aligns the 30cm sides ($WY$ to $MQ$) and 18cm sides ($WX$ to $MN$). Reflecting across $\overline{WY}$ (now aligned with $\overline{MQ}$) maps $X$ to $N$ and $Y$ to $Q$.

Answer:

B. $\overline{WY}$