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how many molecules of atp are created in total after glycolysis, krebs …

Question

how many molecules of atp are created in total after glycolysis, krebs cyc and electron transport chain occur? 2 20 36 32

Explanation:

Brief Explanations
  • Glycolysis produces a net gain of 2 ATP molecules.
  • The Krebs Cycle (Citric Acid Cycle) produces 2 ATP molecules per glucose molecule.
  • The Electron Transport Chain (ETC) is the major ATP - producing stage. NADH and FADH₂ produced in glycolysis and the Krebs Cycle donate electrons to the ETC.
  • Each NADH can produce approximately 2.5 ATP (in a more accurate accounting, considering the shuttle systems for NADH from glycolysis). Glycolysis produces 2 NADH (cytoplasmic), and the Krebs Cycle produces 6 NADH (mitochondrial).
  • Each FADH₂ produces approximately 1.5 ATP. The Krebs Cycle produces 2 FADH₂.
  • The total ATP from NADH: \((2\times2.5)+(6\times2.5)=20\)
  • The total ATP from FADH₂: \(2\times1.5 = 3\)
  • Adding the ATP from glycolysis (2) and Krebs Cycle (2), and the ATP from ETC (20 + 3): \(2+2+(20 + 3)=36\) (using the older, more commonly - taught approximate values for simplicity in basic biology courses). In more recent, refined calculations with consideration of shuttle systems (like the malate - aspartate shuttle), the number is approximately 32.

Answer:

32 (using more accurate modern calculations considering shuttle systems for NADH from glycolysis) or 36 (using older, simplified textbook - style approximations where each NADH gives 3 ATP and each FADH₂ gives 2 ATP in a basic biology course context). If we assume the basic biology course - level calculation (NADH = 3 ATP, FADH₂= 2 ATP):

  • Glycolysis: 2 ATP (net), 2 NADH (cytoplasmic, assume transported as NADH with 3 ATP each in basic calculation) = \(2\times3=6\) ATP from glycolysis NADH
  • Krebs Cycle: 2 ATP, 6 NADH (\(6\times3 = 18\) ATP), 2 FADH₂ (\(2\times2=4\) ATP)
  • Total: \(2+6 + 2+18+4=32\) (if we consider more accurate modern values with 2.5 ATP per NADH and 1.5 ATP per FADH₂) or \(2+(2\times3)+2+(6\times3)+(2\times2)=36\) (basic approximation). But the most accurate answer with modern understanding is 32.