Question

1. how many liters are in 500 milliliters?

a. 0.0005 l
b. 0.05 l
c. 0.5 l
d. 5 l
1 oz = 28 g
1 lb = 0.454 kg
1 kg = 2.2 lbs

1. how many kg are in 12 oz?

a. 0.0336 kg
b. 0.336 kg
c. 33.6 kg
d. 336.kg

1. a 681 g tumor was removed from a womans abdomen. how much did the tumor weigh in pounds?

a. 1 ½ lbs
b. 24 ¹/₃ lbs
c. 150 lbs
d. 309 lbs

1. bobby is eating a well balanced diet and exercising daily. he expects to lose 8 oz a day. how long will it take him to lose 10 kg?

a. 10 days
b. 12 days
c. 20 days

Explanation:

6. Convert milliliters to liters

• We know that \(1\space L = 1000\space mL\).
• To convert \(500\space mL\) to \(L\), we use the formula \(V(L)=\frac{V(mL)}{1000}\).
• Substitute \(V(mL) = 500\) into the formula: \(V(L)=\frac{500}{1000}=0.5\space L\).

7. Convert ounces to kilograms

• Given \(1\space oz = 28\space g\), for \(12\space oz\), the mass in grams is \(m(g)=12\times28 = 336\space g\).
• Since \(1\space kg=1000\space g\), then \(m(kg)=\frac{336}{1000}=0.336\space kg\).

8. Convert grams to pounds

• First, convert grams to kilograms: \(m(kg)=\frac{681}{1000}=0.681\space kg\).
• Then, use \(1\space kg = 2.2\space lbs\). So \(m(lbs)=0.681\times2.2\approx1.5\space lbs\) (since \(1.5 = 1\frac{1}{2}\)).

9. Calculate the time to lose weight

• First, convert the amount of weight to lose from \(kg\) to \(oz\). Since \(1\space kg = 2.2\space lbs\) and \(1\space lb=16\space oz\) (not directly from the given table, but common conversion: \(1\space kg=2.2\times16 = 35.2\space oz\)). For \(10\space kg\), \(m(oz)=10\times35.2 = 352\space oz\).
• Bobby loses \(8\space oz\) per day. Using the formula \(t(days)=\frac{m(total\space oz)}{m(lost\space per\space day)}\). Substitute \(m(total\space oz)=352\) and \(m(lost\space per\space day) = 8\): \(t(days)=\frac{352}{8}=44\) (There might be an error in the problem - assuming using \(1\space kg = 2.2\space lbs\) and \(1\space lb = 16\space oz\) conversion. If we use the given \(1\space oz=28\space g\), \(10\space kg = 10000\space g\), \(m(oz)=\frac{10000}{28}\approx357.14\space oz\), \(t(days)=\frac{357.14}{8}\approx44.64\). But if we assume a wrong - path (using only given \(1\space oz = 28\space g\) and \(1\space lb=0.454\space kg\)): \(10\space kg=\frac{10}{0.454}\space lbs\approx22\space lbs\), \(22\space lbs = 22\times16\space oz = 352\space oz\), \(t=\frac{352}{8} = 44\). But if we consider the options, maybe there is a miscalculation in the problem setup. However, if we use \(1\space kg = 2.2\space lbs\) (from the table) and \(1\space lb = 16\space oz\) (common), \(10\space kg=22\space lbs\), \(22\space lbs = 352\space oz\), \(t = 44\). But if we use \(1\space oz=28\space g\) (from the table) for \(8\space oz\) loss per day (\(8\times28 = 224\space g\) per day), \(10\space kg=10000\space g\), \(t=\frac{10000}{224}\approx44.64\). Since the options are not matching (maybe a problem typo). But if we assume \(1\space kg = 2.2\space lbs\) and \(1\space lb = 16\space oz\) (and the problem has a typo in options, but following the closest - if we consider \(1\space kg = 2.2\space lbs\) and \(1\space lb = 16\space oz\) and \(8\space oz\) loss per day, \(10\space kg = 22\space lbs\), \(22\space lbs=352\space oz\), \(t = 44\). But if we consider \(1\space oz = 28\space g\) (from the table) for \(8\space oz\) loss (\(8\times28=224\space g\) per day), \(10\space kg = 10000\space g\), \(t=\frac{10000}{224}\approx44.64\).

Answer:

1. C. \(0.5\space L\)
2. B. \(0.336\space kg\)
3. A. \(1\frac{1}{2}\space lbs\)
4. (There is an issue with the options. If we assume using \(1\space kg = 2.2\space lbs\) and \(1\space lb = 16\space oz\) (common conversion) for \(10\space kg\): \(10\times2.2\times16 = 352\space oz\), \(t=\frac{352}{8}=44\). But if we follow the given table \(1\space oz = 28\space g\), \(8\space oz = 224\space g\) per day, \(10\space kg=10000\space g\), \(t=\frac{10000}{224}\approx44.64\). The problem might have a typo. If we assume \(1\space kg = 2.2\space lbs\) (from table) and \(1\space lb = 16\space oz\) (common) and \(8\space oz\) loss per day, \(10\space kg = 22\space lbs\), \(22\space lbs=352\space oz\), \(t = 44\). But since no \(44\) option, there is likely an error in the problem. If we consider \(1\space kg = 2.2\space lbs\) (from table) and \(1\space lb = 16\space oz\) (common) and \(8\space oz\) loss per day, \(10\space kg = 22\space lbs\), \(22\space lbs = 352\space oz\), \(t=\frac{352}{8} = 44\). But if we use \(1\space oz=28\space g\) (from table) for \(8\space oz\) loss (\(8\times28 = 224\space g\) per day), \(10\space kg = 10000\space g\), \(t=\frac{10000}{224}\approx44.64\).)