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homework homework 3 in week 1 question 5, r.2.13 part 3 of 7 hw score: …

Question

homework homework 3 in week 1 question 5, r.2.13 part 3 of 7 hw score: 66.67%, 4 of 6 points points: 0 of 1 on the real number line, label the points with coordinates 0, 2, -2, \\(\frac{5}{2}\\), -2.5, \\(\frac{3}{4}\\), and 0.25. label the point with coordinate 0. label the point with coordinate 2. label the point with coordinate -2. help me solve this view an example get more help - clear all final check

Explanation:

Step1: Understand the Coordinates

First, we need to convert all the given coordinates to a common form (decimal or fraction) for easier placement on the number line.

  • \( 0 \) is the origin.
  • \( 2 \) is a positive integer.
  • \( -2 \) is a negative integer.
  • \( \frac{5}{2} = 2.5 \), which is halfway between \( 2 \) and \( 3 \).
  • \( -2.5 \) is halfway between \( -3 \) and \( -2 \).
  • \( \frac{3}{4} = 0.75 \), which is three - quarters of the way from \( 0 \) to \( 1 \).
  • \( 0.25=\frac{1}{4} \), which is a quarter of the way from \( 0 \) to \( 1 \).

Step2: Place \( 0 \)

The point with coordinate \( 0 \) is the origin of the real number line. On the given number line for \( 0 \), we identify the position of \( 0 \) (usually the middle - like point or the point marked as the starting reference).

Step3: Place \( 2 \)

For the number line labeled to place \( 2 \), we move \( 2 \) units to the right of \( 0 \) (assuming each major tick mark is \( 1 \) unit or we calculate the distance based on the scale). If the number line has tick marks, we find the position corresponding to \( 2 \).

Step4: Place \( -2 \)

For the number line labeled to place \( -2 \), we move \( 2 \) units to the left of \( 0 \). We identify the position on the number line that is \( 2 \) units left of the origin.

(Note: Since the problem is about labeling points on a real number line, we assume that the user is expected to mark the points as per their values. For example, for \( 0 \), mark the origin; for \( 2 \), mark the point \( 2 \) units right of \( 0 \); for \( -2 \), mark the point \( 2 \) units left of \( 0 \), and so on for the other points.)

Answer:

To label the points:

  • For \( 0 \): Mark the origin (the middle - like or reference point on the number line for \( 0 \)).
  • For \( 2 \): Mark the point \( 2 \) units to the right of \( 0 \) on its respective number line.
  • For \( -2 \): Mark the point \( 2 \) units to the left of \( 0 \) on its respective number line.
  • For \( \frac{5}{2}=2.5 \): Mark the point halfway between \( 2 \) and \( 3 \).
  • For \( -2.5 \): Mark the point halfway between \( -3 \) and \( -2 \).
  • For \( \frac{3}{4} = 0.75 \): Mark the point \( 0.75 \) units to the right of \( 0 \) (three - quarters of the way from \( 0 \) to \( 1 \)).
  • For \( 0.25=\frac{1}{4} \): Mark the point \( 0.25 \) units to the right of \( 0 \) (a quarter of the way from \( 0 \) to \( 1 \)).

(If we consider the specific number lines given in the problem:

  • For the "Label the point with coordinate \( 0 \)" line: The point is the origin.
  • For the "Label the point with coordinate \( 2 \)" line: The point is \( 2 \) units right of \( 0 \).
  • For the "Label the point with coordinate \( -2 \)" line: The point is \( 2 \) units left of \( 0 \))