Question

1. hl11q6

points: 0/1
alejandra is attempting to drag her 37.6-kg golden retriever across the wooden floor by applying a horizontal force. what force must she apply to move the dog with a constant speed of 0.56 m/s? the coefficient of friction between the dog and the floor is 0.875.
applied force 322 n ×
info attempts: 1/4
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Explanation:

Step1: Calculate normal force

Normal force $N = mg = 37.6\,\text{kg} \times 9.8\,\text{m/s}^2 = 368.48\,\text{N}$

Step2: Calculate friction force

Friction force $f = \mu N = 0.87 \times 368.48\,\text{N} \approx 320.58\,\text{N}$

Step3: Determine applied force

Constant speed means applied force = friction force.

Answer:

321 (rounded to nearest whole number)