Question

here is an equation y = -9/8x + 17. what form is this linear equation in? (circle one) standard form or slope - intercept form. which key features of the graph can you determine from this equation? then determine what they are for the equation. d) slope e) y - intercept f) x - intercept

Explanation:

Step1: Identify the form of the equation

The slope - intercept form of a linear equation is $y = mx + b$, where $m$ is the slope and $b$ is the y - intercept. The given equation $y=-\frac{9}{8}x + 17$ is in slope - intercept form.

Step2: Determine the slope

In the equation $y=-\frac{9}{8}x + 17$, the coefficient of $x$ is the slope $m$. So, the slope $m=-\frac{9}{8}$.

Step3: Determine the y - intercept

In the equation $y=-\frac{9}{8}x + 17$, the constant term is the y - intercept $b$. So, the y - intercept $b = 17$.

Step4: Determine the x - intercept

Set $y = 0$ in the equation $y=-\frac{9}{8}x + 17$. Then $0=-\frac{9}{8}x+17$. Solve for $x$:
First, add $\frac{9}{8}x$ to both sides: $\frac{9}{8}x=17$.
Then multiply both sides by $\frac{8}{9}$: $x=\frac{136}{9}$.

Answer:

The equation is in slope - intercept form.
d) Slope: $-\frac{9}{8}$
e) Y - intercept: $17$
f) X - intercept: $\frac{136}{9}$