Question

if the height and base of the parallelogram shown are each decreased by 2 cm, what is the area of the new parallelogram?
image of a parallelogram with height 8 cm and base 10 cm
\\(\circ\\) \\(40\\,\text{cm}^2\\)
\\(\circ\\) \\(48\\,\text{cm}^2\\)
\\(\circ\\) \\(64\\,\text{cm}^2\\)
\\(\circ\\) \\(76\\,\text{cm}^2\\)

Explanation:

Step1: Calculate new base and height

Original base \(b = 10\space cm\), new base \(b_{new}=10 - 2=8\space cm\)
Original height \(h = 8\space cm\), new height \(h_{new}=8 - 2 = 6\space cm\)

Step2: Calculate area of new parallelogram

Area formula for parallelogram \(A=b\times h\)
Substitute \(b_{new}=8\space cm\) and \(h_{new}=6\space cm\) into formula: \(A = 8\times6\)
\(A=48\space cm^{2}\)

Answer:

\(48\space cm^{2}\)