Question

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analyze this: a rightward force of 354 n is applied to a 12.1 - kg object to accelerate it to the right at 12.1 m/s/s. complete the diagram.
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units
force: n
mass: kg
acceln: m/s/s
color key:

Explanation:

Step1: Apply Newton's second law

Newton's second law is \(F_{net}=ma\). Given \(m = 12.1\space kg\) and \(a=12.1\space m/s^{2}\), then \(F_{net}=12.1\times12.1 = 146.41\space N\) (already provided). In the horizontal direction, \(F_{net}=F_{app}-F_{frict}\). We know \(F_{frict} = 207.59\space N\) and \(F_{net}=146.41\space N\). So, \(F_{app}=F_{net}+F_{frict}\)

Step2: Calculate \(F_{app}\)

Substitute the values: \(F_{app}=146.41 + 207.59=354\space N\)

Answer:

\(F_{app} = 354\space N\)