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midsegments of triangles
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what is the length of the bridge, cd, if walnut avenue is 2640 ft?
ft
Step1: Recall the mid - segment theorem
The mid - segment of a triangle is parallel to the third side and half its length. Here, \(\overline{CD}\) is the mid - segment of the triangle and Walnut Ave is the third side.
Step2: Apply the mid - segment formula
Let the length of Walnut Ave be \(L = 2640\) ft. If \(CD\) is the mid - segment, then \(CD=\frac{1}{2}\times\) length of Walnut Ave. So \(CD=\frac{1}{2}\times2640\).
$$CD = 1320$$
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\(1320\)