Question

guided practice
here is the table of values for the equation (x^2 + y^2 = 25).
fill in the value(s) of (y) when (x = -4), (4), and (5).

(x)	(-5)	(-4)	(-3)	(0)	(3)	(4)	(5)
(y)	(0)		(pm 4)	(pm 5)	(pm 4)

type your answers and then click or tap done.
what are the (y)-values when (x = -4)?
(y = ) (square) or (square)

Explanation:

Step1: Substitute x=-4 into equation

$(-4)^2 + y^2 = 25$ → $16 + y^2 = 25$

Step2: Solve for $y^2$

$y^2 = 25 - 16 = 9$

Step3: Calculate y

$y = \pm\sqrt{9} = \pm3$

Answer:

±3