Question

6.2 grouping: problem 10
(1 point)
factor by grouping:
$x^{2}+3x + 2xy+6y=\square$
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Explanation:

Step1: Group the terms

Group the first two terms and the last two terms:
$$(x^{2}+3x)+(2xy + 6y)$$

Step2: Factor out the common factors from each group

From the first group \(x^{2}+3x\), factor out \(x\): \(x(x + 3)\)
From the second group \(2xy+6y\), factor out \(2y\): \(2y(x + 3)\)
So now we have \(x(x + 3)+2y(x + 3)\)

Step3: Factor out the common binomial factor

Factor out \((x + 3)\) from the expression \(x(x + 3)+2y(x + 3)\)
We get \((x + 3)(x+2y)\)

Answer:

\((x + 3)(x + 2y)\)