Question

1. in a group of cucumber plants, some individuals have dull fruit and others have glossy fruit. in this group, the gene for the fruit sheen trait has two alleles. the allele for dull fruit (f) is dominant over the allele for glossy fruit (f).
2. complete the punnett square to show all possible genotypes of the offspring from a cross between two cucumber plants: parent 1 is homozygous dominant, and parent 2 is heterozygous.

parent 2
blank square blank square
parent 1 blank square blank square blank square
blank square blank square blank square

Explanation:

Step1: Determine Parent Genotypes

Parent 1 (homozygous dominant) has genotype \( FF \), so it can only pass on \( F \) alleles. Parent 2 (heterozygous) has genotype \( Ff \), so it can pass on \( F \) or \( f \) alleles.

Step2: Fill Parent Alleles in Punnett Square

• Parent 1's alleles (both \( F \)) go on the left (rows).
• Parent 2's alleles (\( F \) and \( f \)) go on the top (columns).

Step3: Complete Offspring Genotypes

• Top - left cell: \( F \) (Parent 1) × \( F \) (Parent 2) = \( FF \)
• Top - right cell: \( F \) (Parent 1) × \( f \) (Parent 2) = \( Ff \)
• Bottom - left cell: \( F \) (Parent 1) × \( F \) (Parent 2) = \( FF \)
• Bottom - right cell: \( F \) (Parent 1) × \( f \) (Parent 2) = \( Ff \)

Filling the Punnett Square:

Parent 2 \ Parent 1	\( F \)	\( F \)
\( f \)	\( Ff \)	\( Ff \)

(For the given square structure: Parent 2 top boxes: \( F \), \( f \); Parent 1 left boxes: \( F \), \( F \); Inner boxes (top - left: \( FF \), top - right: \( Ff \), bottom - left: \( FF \), bottom - right: \( Ff \))

Answer:

Parent 2 top boxes: \( F \), \( f \); Parent 1 left boxes: \( F \), \( F \); Inner boxes: top - left \( FF \), top - right \( Ff \), bottom - left \( FF \), bottom - right \( Ff \) (filled as per the above steps in the Punnett square structure).