Question

the graphs below model two transverse waves that maya created with a battle rope. in each graph, the horizontal axis shows the horizontal position of particles of the rope, measured from where maya stood. the vertical axis shows the vertical displacement of the rope, measured from the equilibrium position, at a specific moment in time. assuming the waves are traveling at the same speed, compare the waves. the amplitude is the wavelength is the frequency is

Explanation:

Step1: Determine amplitude

Amplitude is the maximum displacement from equilibrium. For Wave 1, the maximum displacement is \(1\) ft. For Wave 2, the maximum displacement is \(1\) ft. So amplitude is equal for both.

Step2: Determine wavelength

Wavelength is the distance between two consecutive crests (or troughs). For Wave 1, from \(0\) to \(10\) ft is one full cycle (wavelength \(\lambda_1 = 10\) ft). For Wave 2, from \(0\) to \(5\) ft is one full cycle (wavelength \(\lambda_2=5\) ft). So wavelength is greater for Wave 1.

Step3: Use wave - speed formula \(v = f\lambda\)

Since \(v\) is the same (\(v_1 = v_2\)), \(f=\frac{v}{\lambda}\). As \(\lambda_1>\lambda_2\), \(f_1

Answer:

The amplitude is equal for both waves. The wavelength is greater for Wave 1. The frequency is greater for Wave 2.