Question

graphing the cube root function quick check
given the function \\( f(x) = sqrt3{x} \\), find \\( f(216) \\). (1 point)
\\( \circ \\) 14.7
\\( \circ \\) 108
\\( \circ \\) 72
\\( \circ \\) 6

Explanation:

Step1: Understand the function

The function is \( f(x)=\sqrt[3]{x} \), so we need to find the cube root of 216.

Step2: Recall cube of 6

We know that \( 6\times6\times6 = 6^3=216 \).

Step3: Calculate the cube root

Since \( \sqrt[3]{216}=\sqrt[3]{6^3} \), by the property of cube roots \( \sqrt[3]{a^3}=a \), we get \( \sqrt[3]{216} = 6 \). So \( f(216)=6 \).

Answer:

6 (corresponding to the option "6")