Question

graph the solution to the following system of inequalities.\

$$\begin{cases}-3x + 4y\\leq -16\\\\x\\geq 4\\\\y > -8\\end{cases}$$

Explanation:

Answer:

Graph the line \(-3x + 4y=-16\) (solid line, since \(\leq\)), \(x = 4\) (solid line, since \(\geq\)), and \(y=-8\) (dashed line, since \(>\)). For \(-3x + 4y\leq-16\), shade below the line; for \(x\geq4\), shade to the right of \(x = 4\); for \(y>-8\), shade above \(y=-8\). The intersection of these shaded regions is the solution.