Question

graph a right triangle with the two points forming the hypotenuse. using the sides, find the distance between the two points, to the nearest tenth (if necessary). (-7,8) and (-4,-1) \click twice to draw a line. click a segment to erase it.\

Explanation:

Step1: Find the differences in coordinates

For the x - coordinates: $-4 - (-7)=-4 + 7 = 3$
For the y - coordinates: $-1-8=-9$

Step2: Apply the distance formula

The distance formula between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}$. Substituting the values, we get $d=\sqrt{3^2+(-9)^2}=\sqrt{9 + 81}=\sqrt{90}$

Step3: Simplify and round

$\sqrt{90}\approx9.5$ (to the nearest tenth)

Answer:

The distance between the two points is approximately 9.5.