Question

graph a right triangle with the two points forming the hypotenuse. using the sides, find the distance between the two points, to the nearest tenth (if necessary). (7,9) and (2, - 3) click twice to draw a line. click a segment to erase it.

Explanation:

Step1: Identify coordinates

Let $(x_1,y_1)=(7,9)$ and $(x_2,y_2)=(2, - 3)$.

Step2: Calculate difference in x - values

$\Delta x=x_2 - x_1=2 - 7=-5$.

Step3: Calculate difference in y - values

$\Delta y=y_2 - y_1=-3 - 9=-12$.

Step4: Apply distance formula

The distance $d$ between two points $(x_1,y_1)$ and $(x_2,y_2)$ is $d=\sqrt{(\Delta x)^2+(\Delta y)^2}=\sqrt{(-5)^2+(-12)^2}$.

Step5: Simplify the expression

$d=\sqrt{25 + 144}=\sqrt{169}=13$.

Answer:

$13$