Question

graph this line using the slope and y-intercept:
y = -5x
click to select points on the graph.

Explanation:

Step1: Identify slope and y-intercept

The equation is \( y = -5x \), which is in slope - intercept form \( y=mx + b \), where \( m \) is the slope and \( b \) is the y - intercept. Here, \( m=-5 \) and \( b = 0 \). So the y - intercept is at the point \( (0,0) \).

Step2: Use slope to find another point

The slope \( m=-5=\frac{- 5}{1} \). From the y - intercept \( (0,0) \), we can move 1 unit to the right (increase \( x \) by 1) and 5 units down (decrease \( y \) by 5) to get the point \( (0 + 1,0-5)=(1,-5) \). We can also move 1 unit to the left (decrease \( x \) by 1) and 5 units up (increase \( y \) by 5) to get the point \( (0 - 1,0 + 5)=(-1,5) \). Then we can draw a line through these points (like \( (0,0) \) and \( (1,-5) \) or \( (0,0) \) and \( (-1,5) \)) to graph the line \( y=-5x \).

Answer:

To graph \( y = - 5x \), plot the y - intercept \( (0,0) \). Then use the slope \( - 5 \) (rise - over - run: for a run of 1, rise of - 5) to find another point (e.g., \( (1,-5) \) or \( (-1,5) \)) and draw a line through these points.