Question

graph the image of δtuv after a dilation with a scale factor of 3, centered at the origin.

Explanation:

Step1: Identify original coordinates

From graph: \( T(-3, -1) \), \( U(3, -1) \), \( V(-3, 2) \)

Step2: Apply dilation rule

Multiply each coordinate by scale factor 3:
\( T' = (-3×3, -1×3) = (-9, -3) \)
\( U' = (3×3, -1×3) = (9, -3) \)
\( V' = (-3×3, 2×3) = (-9, 6) \)

Step3: Plot image triangle

Graph \( \Delta T'U'V' \) with points \( (-9,-3) \), \( (9,-3) \), \( (-9,6) \)

Answer:

The image triangle has vertices at \( (-9, -3) \), \( (9, -3) \), and \( (-9, 6) \) (plot these points to form the dilated triangle).