Question

graph the image of square stuv after a rotation 270° counterclockwise around the origin.

Explanation:

Step1: Recall the rotation rule

The rule for a \(270^{\circ}\) counter - clockwise rotation around the origin is \((x,y)\to(y, - x)\).

Step2: Apply the rule to each vertex

• For vertex \(S(0,3)\): Using the rule \((x,y)\to(y, - x)\), we get \(S'(3,0)\).
• For vertex \(T(7,3)\): Using the rule \((x,y)\to(y, - x)\), we get \(T'(3,-7)\).
• For vertex \(U(7,10)\): Using the rule \((x,y)\to(y, - x)\), we get \(U'(10,-7)\).
• For vertex \(V(0,10)\): Using the rule \((x,y)\to(y, - x)\), we get \(V'(10,0)\).

Answer:

Plot the points \(S'(3,0)\), \(T'(3,-7)\), \(U'(10,-7)\), \(V'(10,0)\) and connect them to form the rotated square.