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graph the image of parallelogram bcde after a reflection over the y - a…

Question

graph the image of parallelogram bcde after a reflection over the y - axis.

Explanation:

Step1: Find coordinates of original points

Assume \( B(-7,-7)\), \(C(-6,-5)\), \(D(-3,-2)\), \(E(-2,-4)\)

Step2: Apply reflection rule over \(y\) - axis

The rule for reflection over the \(y\) - axis is \((x,y)\to(-x,y)\)
For point \(B(-7,-7)\): \((-7,-7)\to(7,-7)\)
For point \(C(-6,-5)\): \((-6,-5)\to(6,-5)\)
For point \(D(-3,-2)\): \((-3,-2)\to(3,-2)\)
For point \(E(-2,-4)\): \((-2,-4)\to(2,-4)\)

Step3: Plot the new points

Plot \(B'(7,-7)\), \(C'(6,-5)\), \(D'(3,-2)\), \(E'(2,-4)\) on the coordinate plane and connect them to form the reflected parallelogram.

Answer:

Plot the points \((7,-7)\), \((6,-5)\), \((3,-2)\), \((2,-4)\) and connect them.