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Question
graph the image of k(-10, 10) after a reflection over the y-axis.
Step1: Recall the reflection rule
When reflecting a point \((x,y)\) over the \(y\) - axis, the rule is \((x,y)\to(-x,y)\).
Step2: Apply the rule to the point \(K(-10,10)\)
For the point \(K(-10,10)\), where \(x = - 10\) and \(y=10\). Using the rule \((x,y)\to(-x,y)\), we substitute \(x=-10\) into \(-x\). So \(-x=-(-10) = 10\) and \(y = 10\) remains the same.
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The image of the point \(K(-10,10)\) after reflection over the \(y\) - axis is \(K'(10,10)\). To graph it, locate the point \((10,10)\) on the coordinate plane (10 units to the right of the \(y\) - axis and 10 units above the \(x\) - axis).