Question

graph the following function on the axes provided. $f(x)=\begin{cases}x + 2&\text{for }-4leq x<1\\x + 1&\text{for }1

Explanation:

Step1: Find endpoints for $y = x + 2$

For $x=-4$, $y=-4 + 2=-2$. For $x = 1$, $y=1 + 2 = 3$ (but $x = 1$ is not included in this part, so we have an open - circle at $(1,3)$ and a closed - circle at $(-4,-2)$ and draw a line segment for $-4\leq x<1$.

Step2: Find endpoints for $y = x + 1$

For $x = 1$, $y=1+1 = 2$ (open - circle as $x = 1$ is not included in this part). For $x = 6$, $y=6 + 1=7$ (closed - circle). Draw a line segment for $1

Answer:

Graph a line segment from $(-4,-2)$ (closed - circle) to $(1,3)$ (open - circle) for $y=x + 2$ with $-4\leq x<1$ and a line segment from $(1,2)$ (open - circle) to $(6,7)$ (closed - circle) for $y=x + 1$ with $1