Question

1. a good component in a shorted rl series circuit

a measures 0 volts across it
b causes minimum current
c causes current to decrease
d measures a higher voltage across it

Explanation:

In a shorted RL series circuit, when a component is shorted, the voltage across it is \(0\) volts. This is because a short - circuit provides a path of zero resistance, and according to Ohm's law \(V = IR\), if \(R = 0\), then \(V=0\) (assuming \(I\) is finite).

• Option b: A shorted component in a series circuit would actually cause the current to increase (since total resistance decreases, \(I=\frac{V}{R_{total}}\) and \(R_{total}\) becomes smaller), not minimum current.
• Option c: As mentioned above, current increases, not decreases.
• Option d: Since the component is shorted (\(R = 0\)), the voltage across it is \(0\), not higher.

Answer:

A. measures 0 volts across it