Question

the goals against average (a) for a professional hockey goalie is determined using the formula (a = 60 left(\frac{g}{t}
ight)). in the formula, (g) represents the number of goals scored against the goalie and (t) represents the time played, in minutes.

which is an equivalent equation solved for (g)?

(\bigcirc \frac{at}{60} = g)

(\bigcirc \frac{a}{60t} = g)

(\bigcirc \frac{60a}{t} = g)

(\bigcirc 60at = g)

Explanation:

Isolate the fraction term

Divide both sides of the equation by \(60\):

$$ \frac{A}{60} = \frac{g}{t} $$

Solve for g

Multiply both sides of the equation by \(t\):

$$ g = \frac{At}{60} $$

Answer:

• (A) \(\frac{At}{60} = g\) (Correct answer)
• (B) \(\frac{A}{60t} = g\)
• (C) \(\frac{60A}{t} = g\)
• (D) \(60At = g\)