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given: right \\( \\triangle a b d \\) and right \\( \\triangle c b d \\…

Question

given: right \\( \triangle a b d \\) and right \\( \triangle c b d \\)
prove: \\( \triangle a b d \cong \triangle c b d \\)
proof:
find the length of \\( \overline{a d} \\)
\\( \

$$\begin{aligned} a d & = \\sqrt{\\left(x_{2}-x_{1}\ ight)^{2}+\\left(y_{2}-y_{1}\ ight)^{2}} \\\\ & = \\sqrt{(4 - 0)^{2}+(0 - 0)^{2}} \\\\ & = \\sqrt{4^{2}} = \\end{aligned}$$

\\)
find the length of \\( \overline{d c} \\)
\\( \

$$\begin{aligned} d c & = \\sqrt{\\left(x_{2}-x_{1}\ ight)^{2}+\\left(y_{2}-y_{1}\ ight)^{2}} \\\\ & = \\sqrt{(8 - 4)^{2}+(0 - 0)^{2}} \\\\ & = \\sqrt{4^{2}} = \\end{aligned}$$

\\)

  • \\( \overline{a d} \cong \overline{d c} \\) by the
  • \\( \overline{b d} \cong \overline{b d} \\) by the
  • \\( \triangle a b d \cong \triangle c b d \\) by the f congruence theorem

a. 4
b. reflexive property of \\( \cong \\)
c. segment property
d. 8
e. 16
f. leg leg
g. definition of \\( \cong \\)

Explanation:

Step1: Calculate length of \( \overline{AD} \)

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Step2: Calculate length of \( \overline{DC} \)

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Since \( AD = DC=4 \), \( \overline{AD}\cong\overline{DC} \) by the definition of congruent segments (\( \text{Definition of }\cong \)).

Step3: Analyze \( \overline{BD}\cong\overline{BD} \)

\( \overline{BD}\cong\overline{BD} \) by the Reflexive Property of \( \cong \) (a segment is congruent to itself).

Step4: Determine congruence of triangles

For right - triangles \( \triangle ABD \) and \( \triangle CBD \), we have two pairs of congruent legs (\( \overline{AD}\cong\overline{DC} \) and \( \overline{BD}\cong\overline{BD} \)). So, \( \triangle ABD\cong\triangle CBD \) by the Leg - Leg (\( LL \)) Congruence Theorem for right - triangles.

Answer:

For the length of \( \overline{AD} \): \( 4 \) (a). For the length of \( \overline{DC} \): \( 4 \) (a). \( \overline{AD}\cong\overline{DC} \) by the \( \text{Definition of }\cong \) (g). \( \overline{BD}\cong\overline{BD} \) by the \( \text{Reflexive Property of }\cong \) (b). \( \triangle ABD\cong\triangle CBD \) by the \( \text{Leg - Leg} \) (\( f \)) Congruence Theorem.