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Question
- given the rhombus ( j k l m, m k = 24 ). ( j l = 20 ), and ( m angle m k l = 50 ^ { circ } ). determine the missing measures. ( n k = ) ( m angle k n l = ) ( n l = ) ( m angle k j l = ) ( m l = ) ( m angle m l k = ) ( m angle j k m = ) ( m angle j m l = )
Step1: Properties of rhombus diagonals
In a rhombus, the diagonals bisect each other. So, if \(MK = 24\), then \(NK=\frac{MK}{2}\).
\(NK=\frac{24}{2}=12\)
If \(JL = 20\), then \(NL=\frac{JL}{2}\).
\(NL=\frac{20}{2} = 10\)
Step2: Right - angle property of rhombus diagonals
The diagonals of a rhombus are perpendicular to each other. So, \(m\angle KNL=90^{\circ}\)
Step3: Using triangle angle - sum property
In right - triangle \(KNL\), \(m\angle KJL\) and \(m\angle MKL\) are complementary (since \(\angle KNL = 90^{\circ}\) and \(\angle KJL\) and \(\angle MKL\) are non - right angles of \(\triangle KNL\)). So, \(m\angle KJL=90^{\circ}-m\angle MKL\)
\(m\angle KJL = 90^{\circ}-50^{\circ}=40^{\circ}\)
Step4: Pythagorean theorem for side length
Using the Pythagorean theorem in \(\triangle KNL\) to find \(ML\) (since all sides of a rhombus are equal). \(ML=\sqrt{NK^{2}+NL^{2}}\)
\(ML=\sqrt{12^{2}+10^{2}}=\sqrt{144 + 100}=\sqrt{244}=2\sqrt{61}\approx15.62\)
Step5: Angle - bisecting property of rhombus diagonals
The diagonals of a rhombus bisect the vertex angles. So, \(m\angle JKM=m\angle MKL = 50^{\circ}\)
Step6: Opposite angles and adjacent angles in a rhombus
Adjacent angles of a rhombus are supplementary. Let \(m\angle MLK\). Since \(m\angle MKL = 50^{\circ}\), and the diagonal \(MK\) bisects \(\angle MLK\), \(m\angle MLK=2\times m\angle MKL\)
\(m\angle MLK = 100^{\circ}\)
Step7: Using parallel sides and alternate interior angles
Since \(JK\parallel ML\) in rhombus \(JKLM\), \(m\angle JML=m\angle KJL\) (alternate interior angles for \(JK\parallel ML\) and transversal \(JL\))
\(m\angle JML = 40^{\circ}\)
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\(NK = 12\), \(NL = 10\), \(ML\approx15.62\), \(m\angle JKM = 50^{\circ}\), \(m\angle KNL=90^{\circ}\), \(m\angle KJL = 40^{\circ}\), \(m\angle MLK = 100^{\circ}\), \(m\angle JML = 40^{\circ}\)