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Question
given: ( \triangle kjl cong \triangle nml ) n is the midpoint of ( overline{mo} ). prove: kjon is a parallelogram. 7. ( overline{kj} parallel overline{no} ) 7. 8. 8.
Step1: Use the property of congruent triangles
Since \(\triangle KJL\cong\triangle NML\), we have \(KJ = NM\) (corresponding parts of congruent triangles are equal).
Step2: Use the mid - point property
Because \(N\) is the mid - point of \(MO\), \(NM=NO\). Then \(KJ = NO\) (by substitution).
Step3: Use the definition of a parallelogram
A quadrilateral with one pair of opposite sides parallel (\(\overline{KJ}\parallel\overline{NO}\)) and equal (\(KJ = NO\)) is a parallelogram.
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- If two triangles are congruent, their corresponding sides are equal. Also, mid - point divides a line segment into two equal parts.
- \(KJ = NO\); A quadrilateral with one pair of opposite sides parallel and equal is a parallelogram.