QUESTION IMAGE
Question
given the functions f(x), the piecewise defined function and g(x), the straight line, shown, answer the following questions. show all work 7/8
- find f(2)
- find g(-2)
- find (f + g)(-1)
- find (f - g)(1)
Question 7: Find \( f(2) \)
Step 1: Analyze the graph of \( f(x) \)
The function \( f(x) \) is a piecewise - defined function (the green graph). We need to find the \( y \) - value of \( f(x) \) when \( x = 2 \). By looking at the graph of \( f(x) \), we can see the coordinates of the points on the graph. For \( x=2 \), we locate the point on the \( f(x) \) graph with \( x \) - coordinate 2. From the graph, we observe that when \( x = 2 \), the \( y \) - coordinate (the value of \( f(x) \)) is 4.
Step 1: Analyze the graph of \( g(x) \)
The function \( g(x) \) is a straight - line (the blue graph). The equation of a straight line in slope - intercept form is \( y=mx + b \), where \( m \) is the slope and \( b \) is the \( y \) - intercept. First, we find the slope of \( g(x) \). Let's take two points on \( g(x) \). From the graph, we can see that the line passes through \( (0,0) \) and \( ( - 8,8) \) (or other pairs of points). The slope \( m=\frac{y_2 - y_1}{x_2 - x_1}=\frac{0 - 8}{0-( - 8)}=\frac{- 8}{8}=- 1 \). The \( y \) - intercept \( b = 0 \) (since it passes through the origin \( (0,0) \)). So the equation of \( g(x) \) is \( g(x)=-x \).
Step 2: Substitute \( x=-2 \) into \( g(x) \)
Substitute \( x = - 2 \) into \( g(x)=-x \). Then \( g(-2)=-(-2)=2 \). We can also verify this by looking at the graph: when \( x=-2 \), we find the point on the \( g(x) \) line with \( x \) - coordinate - 2, and the \( y \) - coordinate is 2.
Step 1: Recall the definition of function addition
By the definition of function addition, \( (f + g)(x)=f(x)+g(x) \). So \( (f + g)(-1)=f(-1)+g(-1) \).
Step 2: Find \( f(-1) \)
Looking at the graph of \( f(x) \) (the green graph), when \( x=-1 \), we find the \( y \) - value of \( f(x) \). From the graph, when \( x = - 1 \), \( f(-1)=1 \).
Step 3: Find \( g(-1) \)
Using the equation of \( g(x)=-x \) (from question 8), substitute \( x=-1 \) into \( g(x) \). We get \( g(-1)=-(-1) = 1 \).
Step 4: Calculate \( (f + g)(-1) \)
\( (f + g)(-1)=f(-1)+g(-1)=1 + 1=2 \).
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\( f(2)=4 \)