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Question
gh bisects cf, cf = 2y - 2, and cd = 3y - 11. find cd.
Step1: Use the property of bisecting
Since \( \overline{GH} \) bisects \( \overline{CF} \), then \( CE = CD \). So \( 2y - 2=3y - 11 \).
Step2: Solve the equation for \( y \)
Subtract \( 2y \) from both sides: \( - 2=y - 11 \).
Add 11 to both sides: \( y = 9 \).
Step3: Find the value of \( CD \)
Substitute \( y = 9 \) into the expression for \( CD \) (\( CD=3y - 11 \)).
\( CD=3\times9 - 11=27 - 11 = 16 \).
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