QUESTION IMAGE
Question
geometry support unit 1—introduction to geometry notes
- given: ( 6x - 4 = 3x + 8 ).
prove: ( x = 4 )
Step1: Subtract \(3x\) from both sides
\(6x - 4-3x=3x + 8-3x\)
\(3x-4 = 8\) (Subtraction Property of Equality)
Step2: Add \(4\) to both sides
\(3x-4 + 4=8 + 4\)
\(3x=12\) (Addition Property of Equality)
Step3: Divide both sides by \(3\)
\(\frac{3x}{3}=\frac{12}{3}\)
\(x = 4\) (Division Property of Equality)
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| Statement | Reason |
|---|---|
| \(6x-4-3x=3x + 8-3x\) | Subtraction Property of Equality |
| \(3x-4 = 8\) | Simplification |
| \(3x-4 + 4=8 + 4\) | Addition Property of Equality |
| \(3x=12\) | Simplification |
| \(\frac{3x}{3}=\frac{12}{3}\) | Division Property of Equality |
| \(x = 4\) | Simplification |