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geometry the length of a rectangle is 8 feet, and its area is less than…

Question

geometry the length of a rectangle is 8 feet, and its area is less than 168 square feet. select an inequality that represents the possible widths x (in feet) of the rectangle. then solve the inequality.
options:
168x < 8
168 < 8x
8x < 168
2x + 16 < 168
the solution of the inequality is \boxed{}.

Explanation:

Step1: Recall area of rectangle

The area \( A \) of a rectangle is given by \( A = \text{length} \times \text{width} \). Here, length is 8 feet, width is \( x \) feet, and area is less than 168 square feet. So the inequality is \( 8x < 168 \).

Step2: Solve the inequality

To solve \( 8x < 168 \), divide both sides by 8: \( \frac{8x}{8} < \frac{168}{8} \), which simplifies to \( x < 21 \).

Answer:

The inequality is \( 8x < 168 \) and the solution is \( x < 21 \).