Question

gebra 1 sem a cr- a\
s of probability and geometry\
what is the value of b?\
triangle with angles 58°, b°, 61°

Explanation:

Step1: Recall triangle angle sum

The sum of angles in a triangle is \(180^\circ\).

Step2: Set up the equation

Let the angles be \(58^\circ\), \(61^\circ\), and \(B^\circ\). So, \(58 + 61 + B = 180\).

Step3: Solve for B

First, calculate \(58 + 61 = 119\). Then, \(B = 180 - 119 = 61\)? Wait, no, wait: \(180 - 58 - 61 = 61\)? Wait, \(58 + 61 = 119\), \(180 - 119 = 61\)? Wait, no, \(58 + 61 = 119\), \(180 - 119 = 61\)? Wait, no, \(58 + 61 = 119\), \(180 - 119 = 61\)? Wait, no, let's recalculate: \(180 - 58 - 61 = 180 - (58 + 61) = 180 - 119 = 61\)? Wait, no, \(58 + 61 = 119\), \(180 - 119 = 61\)? Wait, that can't be. Wait, no, \(58 + 61 = 119\), \(180 - 119 = 61\)? Wait, maybe I made a mistake. Wait, \(58 + 61 = 119\), \(180 - 119 = 61\)? Wait, no, \(180 - 58 = 122\), \(122 - 61 = 61\). Yes, so \(B = 61\)? Wait, no, wait the triangle has angles 58, 61, and B. So 58 + 61 + B = 180. So B = 180 - 58 - 61 = 61. Wait, that's correct? Wait, 58 + 61 is 119, 180 - 119 is 61. So B is 61 degrees.

Answer:

\(61\)