Question

for a gas with fixed amount, if its initial conditions are ( p_1 = 200 ) kpa, ( v_1 = 10 ) l, ( t_1 = 300 ) k, and its final conditions are ( p_2 = 150 ) kpa, ( t_2 = 400 ) k, what is the final volume ( v_2 )?

Explanation:

Step1: Write the combined gas law formula

The combined gas law is \(\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\).

Step2: Rearrange the formula to solve for \(V_2\)

$$
LATEXBLOCK0
$$

Step3: Substitute the given values

Substitute \(P_1 = 200\space kPa\), \(V_1=10\space L\), \(T_1 = 300\space K\), \(P_2=150\space kPa\), and \(T_2 = 400\space K\) into the formula:

$$
LATEXBLOCK1
$$

Answer:

\(V_2\approx17.8\space L\)