Question

6 friends are selling crafts at a show. they each need to pay \\$7.20 to cover the table rental. they each sell 3 items. if every item is the same price, and the 6 friends make a total of \\$25.20, what was the sale price of each item?

\\$1.00
\\$1.80
\\$3.80
\\$4.20

Explanation:

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<reasoning>

Set up the equation for total profit

\[

$$\begin{aligned} &\text{Let } p \text{ be the sale price of each item.}\\ &6 \times (3p - 7.20) = 25.20 \end{aligned}$$

\]

Solve for the price per item

\[

$$\begin{aligned} &3p - 7.20 = \frac{25.20}{6}\\ &3p - 7.20 = 4.20\\ &3p = 4.20 + 7.20\\ &3p = 11.40\\ &p = \frac{11.40}{3}\\ &p = 3.80 \end{aligned}$$

\]
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<answer>
<mcq-option>(A) $1.00</mcq-option>
<mcq-option>(B) $1.80</mcq-option>
<mcq-correct>(C) $3.80</mcq-correct>
<mcq-option>(D) $4.20</mcq-option>
</answer>

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Answer:

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<reasoning>

Set up the equation for total profit

\[

$$\begin{aligned} &\text{Let } p \text{ be the sale price of each item.}\\ &6 \times (3p - 7.20) = 25.20 \end{aligned}$$

\]

Solve for the price per item

\[

$$\begin{aligned} &3p - 7.20 = \frac{25.20}{6}\\ &3p - 7.20 = 4.20\\ &3p = 4.20 + 7.20\\ &3p = 11.40\\ &p = \frac{11.40}{3}\\ &p = 3.80 \end{aligned}$$

\]
</reasoning>

<answer>
<mcq-option>(A) $1.00</mcq-option>
<mcq-option>(B) $1.80</mcq-option>
<mcq-correct>(C) $3.80</mcq-correct>
<mcq-option>(D) $4.20</mcq-option>
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