Question

if the frequency of a note is 512 hz and the speed of sound is 340 m/s at room temperature. what is the wavelength of this sound?

Explanation:

Step1: Recall the wave equation

The wave equation is \(v = f\lambda\), where \(v\) is the speed of the wave, \(f\) is the frequency, and \(\lambda\) is the wavelength. We need to solve for \(\lambda\), so \(\lambda=\frac{v}{f}\).

Step2: Substitute the given values

Given \(v = 340\space m/s\) and \(f=512\space Hz\). Then \(\lambda=\frac{340}{512}\).

Step3: Calculate the value

\(\frac{340}{512}\approx0.66\space m\)

Answer:

\(0.66\space m\)