Question

p² is the frequency of homozygous dominants
2 pq is the frequency of heterozygous individuals
q² is the frequency of homozygous recessives
if 10% of the population has a recessive disorder then 0.10 is equal to q²
√0.1 = q; q = 0.32.
therefore p = 1 - 0.32: p = 0.68
value: 10
from this information above what percent of the population is homozygous dominant?
○ a. 29%
○ b. 46%
○ c. 75%
○ d. 36%
check answer
value: 10
if you monitered this populations and in five generations the allele frequency is p = 0.69 and q = 0.31, what would you say about this population?
○ a. the allele frequency is different therefore the population is evolving
○ b. the allele frequency has not changed and therefore the population is not evolving
○ c. we would need to look at least 25 generations to see in the allele frequency is changing

Explanation:

Step1: Calculate homozygous dominant frequency

The formula for the frequency of homozygous dominants is \(p^{2}\). Given \(p = 0.68\), we calculate \(p^{2}=(0.68)^{2}=0.4624\approx46\%\)

Step2: Analyze population evolution

Evolution is defined as a change in allele frequencies over time. Initially \(p = 0.68\) and \(q=0.32\). After five generations \(p = 0.69\) and \(q = 0.31\). Since the allele frequencies (\(p\) and \(q\)) have changed, the population is evolving.

Answer:

For the first question: B. 46%
For the second question: A. The allele frequency is different therefore the population is evolving