Question

1. freckles (f) are dominant to no freckles (f). a heterozygous mother (____) and heterozygous father (____) have a baby. f = freckles, f = no freckles

genotype phenotype
possibility 1: ____ ____
possibility 2: ____ ____
possibility 3: ____ ____
possibility 4: ____ ____

Explanation:

Step1: Determine the genotypes of parents

Since both parents are heterozygous, their genotypes are \(Ff\).

Step2: Create a Punnett square

	\(F\)	\(f\)
\(f\)	\(Ff\)	\(ff\)

Step3: Analyze genotypes and phenotypes

• Possibility 1: Genotype \(FF\), Phenotype: Freckles (because \(F\) is dominant)
• Possibility 2: Genotype \(Ff\), Phenotype: Freckles (because \(F\) is dominant)
• Possibility 3: Genotype \(Ff\), Phenotype: Freckles (because \(F\) is dominant)
• Possibility 4: Genotype \(ff\), Phenotype: No freckles (since there is no dominant \(F\) allele)

Answer:

Possibility 1: \(FF\), Freckles
Possibility 2: \(Ff\), Freckles
Possibility 3: \(Ff\), Freckles
Possibility 4: \(ff\), No freckles