Question

four students are pushed in a chair with wheels. their masses and the forces acting on them are recorded in the table below. which student has the greatest acceleration as they are pushed in the chair? student 1 student 2 student 3 student 4

Explanation:

Step1: Calculate acceleration for Student 1

Using Newton's second law \(F = ma\), so \(a=\frac{F}{m}\). For Student 1: \(a_1=\frac{240}{80}=3\space m/s^{2}\)

Step2: Calculate acceleration for Student 2

For Student 2: \(a_2=\frac{110}{50}=2.2\space m/s^{2}\)

Step3: Calculate acceleration for Student 3

For Student 3: \(a_3=\frac{100}{60}\approx1.67\space m/s^{2}\)

Step4: Calculate acceleration for Student 4

For Student 4: \(a_4=\frac{170}{40}=4.25\space m/s^{2}\)

Answer:

Student 4