QUESTION IMAGE
Question
four interior angles of a pentagon measure 156°, 72°, 98°, and 87°. what is the measure of the final interior angle? 108° 127° 150° 487°
Step1: Find the sum of interior angles of a pentagon
The formula for the sum of interior angles of a polygon is \((n - 2)\times180^{\circ}\), where \(n\) is the number of sides. For a pentagon, \(n = 5\).
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Step2: Calculate the sum of the four given angles
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Step3: Find the measure of the fifth angle
Let the fifth angle be \(x\). Then \(x=540^{\circ}-413^{\circ}\)
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x = 127^{\circ}
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B. \(127^{\circ}\)